# How do you factor the monomial -35a^3c^2 completely?

$- 1 \times 5 \times 7 \times a \times a \times a \times c \times c$
The negative is a factor. 1 is a factor. 35 can be factored into $5 \times 7$
${a}^{3}$ = $a \times a \times a$ a times itself three times.
${c}^{2}$ = $c \times c \text{ }$this is c times itself two times.