# How do you factor the sum or difference of two cubes 64m^3n^3+216m^3p^3?

8${m}^{3}$ (2n+3p) (4${n}^{2}$ -6np + 9${p}^{2}$)
Write the numbers as perfect cubes by first taking out 8${m}^{3}$ as a common factor like this 8${m}^{3}${ ${\left(2 n\right)}^{3}$ + ${\left(3 p\right)}^{3}$}. Using the algebraic identity for factorising the sum of two cubes, the factorisation would be 8${m}^{3}$ (2n+3p) (4${n}^{2}$ -6np + 9${p}^{2}$)