# How do you factor the trinomial 49x^2-21x+2?

$\left(7 x - 1\right) \left(7 x - 2\right)$
You have a square number, 49 as your ${x}^{2}$ coefficient. Therefore your factors within your parentheses are both going to start with $7 x$ Your centre term has a negative coefficient and your last term is a positive. This indicates that the signs inside will both be negative. Lastly, negative 1 multiplied by negative 2 gives you $+ 2$