# How do you factor the trinomial v^3 - 4v^2 - 45v?

Apr 9, 2016

$v \left(v - 9\right) \left(v + 5\right)$

#### Explanation:

Taking $v$ out as a common factor, we get:

$v \left({v}^{2} - 4 v - 45\right)$

Now what we have is a quadratic multiplied by a common factor.
Factorising the quadratic we get the fully factored function:

$v \left(v - 9\right) \left(v + 5\right)$