# How do you factor w^2 + 4t^2?

May 10, 2015

${w}^{2} + 4 {t}^{2}$ is already completely factored - at least if you are restricted to real coefficients.

If you were allowed complex coefficients, it would be possible to factor completely as:

${w}^{2} + 4 {t}^{2} = \left(w + 2 i t\right) \left(w - 2 i t\right)$
(where $i = \sqrt{- 1}$)

...but neither of these linear factors has all real coefficients.