# How do you factor w^2 + 4t^2?

${w}^{2} + 4 {t}^{2}$ is already completely factored - at least if you are restricted to real coefficients.
${w}^{2} + 4 {t}^{2} = \left(w + 2 i t\right) \left(w - 2 i t\right)$
(where $i = \sqrt{- 1}$)