How do you factor #w^2 + 4t^2#?

1 Answer
George C.
May 10, 2015

#w^2+4t^2# is already completely factored - at least if you are restricted to real coefficients.

If you were allowed complex coefficients, it would be possible to factor completely as:

#w^2+4t^2 = (w+2it)(w-2it)#
(where #i = sqrt(-1)#)

...but neither of these linear factors has all real coefficients.

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