How do you factor #x^2+3xa+6x 18a#?

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Answer 1 · 2015-05-14T04:45:57

Note: I assume there is a typo. The expression could be

#x^2+3xa+6x + 18a#

We can factor this expression using Grouping. Making groups of 2 terms each, we get:

#= (x^2+3xa)+(6x + 18a)#

#x# is common to both the terms in the first group, and #6# is common to both the terms in the second group.

#= x(x+3a)+6(x + 3a)#

#x+3a# is common to both the terms

#=color(green)((x+3a)(x+6)#