How do you factor #x^2 - x - 6#?

1 Answer

Find factors of #-6#, then add them up individually to find the ones that add to #-1# and you'll get to #(x-3)(x+2)#

Explanation:

Let's start with the original:

#x^2-x-6#

The way to factor something is to 2 numbers that will add up to #-1# but multiply to #-6#. To do that, let's think about what we need to multiply to get to #-6# - and that is (I'll put them in a list):

#(1*-6), (-1*6), (2*-3), (-2*3)#.

If we add those up individually we get

#-5, 5,-1,1#

So we can use the #(2,-3)# like this

#(x-3)(x+2)#

and we're done.