# How do you factor x^3 + (2)x^2 + (4)x + 8?

${x}^{3} + 2 {x}^{2} + 4 x + 8 = \left(x + 2\right) \left({x}^{2} + 4\right) = \left(x + 2\right) \left(x + 2 i\right) \left(x - 2 i\right)$
The solution to a cubic is not simple. This one has an 'obvious' factor.Rewrite the equation ${x}^{3} + 4 x + 2 {x}^{2} + 8 = x \left({x}^{2} + 4\right) + 2 \left({x}^{2} + 4\right) = \left(x + 2\right) \left({x}^{2} + 4\right)$