Question

How do you factor `x^3+27=0`?

Answer 1

`(x+3)(x^2-3x+9)=0`

Explanation:

We have a standard polynomial on LHS of the form `a^3+b^3`, whose one factor is `(a+b)`. So one factor is `(x+3)`

`x^3+27=0`

`hArrx^3+3x^2-3x^2-9x+9x+27=0`

or `x^2(x+3)-3x(x+3)+9(x+3)=0`

or `(x+3)(x^2-3x+9)=0`