# How do you factor x^3 + 3x^2 - 4x - 12?

Apr 28, 2015

Collect $x$ between the first and third term and $3$ between the second and fourth.
After this collect the bracket and you'll get your two factors.

If you have difficulties have a look at the solution below.
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Solution:
$x \left({x}^{2} - 4\right) + 3 \left({x}^{2} - 4\right) =$
$\left({x}^{2} - 4\right) \left(x + 3\right)$