# How do you factor x^3 + 4x^2 - 9x - 6 =0?

Nov 26, 2015

$\left(x + 2\right) \left(x + 3\right) \left(x - 3\right) \left(2 {x}^{2} - 3\right) = 0$

#### Explanation:

Whenever you have a polynomial with more than $3$ terms, it is always a good idea to group your like terms together:

${x}^{3} + 4 {x}^{2} - 9 x - 6 = 0$
${x}^{3} - 9 x + 4 {x}^{2} - 6 = 0$
$x \left({x}^{2} - 9\right) + 2 \left(2 {x}^{2} - 3\right) = 0$
$x \left(x + 3\right) \left(x - 3\right) + 2 \left(2 {x}^{2} - 3\right) = 0$
$\left(x + 2\right) \left(x + 3\right) \left(x - 3\right) \left(2 {x}^{2} - 3\right) = 0$