How do you factor #-x^3 +6x^2 -x =5#?

1 Answer
Lizzy P.
Oct 6, 2015

#x(-x^2+6x-1)=5#

Explanation:

  1. Start by finding a variable/term that all of the numbers have in common.
  2. Factor out that term and simplify.
  3. #x# is common in all of the terms, so we can factor this out of the equation.
  4. Because all numbers have an exponent of one, factor out #x^1# from all of the terms containing #x#.
  5. #-x^3-x1=-x^2#
  6. #6x^2-x^1=6x#
  7. #x# can be taken out of itself once, and we use 1 as a place holder for any number that has been factored out of the equation.
Related questions
See all questions in Factoring Completely
Impact of this question
1418 views around the world
You can reuse this answer
Creative Commons License