How do you factor #-x^3 +6x^2 -x =5#?

1 Answer
Oct 6, 2015

Answer:

#x(-x^2+6x-1)=5#

Explanation:

  1. Start by finding a variable/term that all of the numbers have in common.
  2. Factor out that term and simplify.
  3. #x# is common in all of the terms, so we can factor this out of the equation.
  4. Because all numbers have an exponent of one, factor out #x^1# from all of the terms containing #x#.
  5. #-x^3-x1=-x^2#
  6. #6x^2-x^1=6x#
  7. #x# can be taken out of itself once, and we use 1 as a place holder for any number that has been factored out of the equation.