Question

How do you factor `x^3 + 8x^2 = -16x`?

Answer 1

First you take everything to one side (by adding `16x` to both sides)

Explanation:

`->x^3+8x^2+16x=0`

You can take out `x` from all terms:
`->x(x^2+8x+16)=0`

The quadratic part should be easy to factor:
`->x(x+4)^2=0`

Solution: `x=0orx=-4`