# How do you factor  x^3 + 8x^2 = -16x ?

May 22, 2016

First you take everything to one side (by adding $16 x$ to both sides)

#### Explanation:

$\to {x}^{3} + 8 {x}^{2} + 16 x = 0$

You can take out $x$ from all terms:
$\to x \left({x}^{2} + 8 x + 16\right) = 0$

The quadratic part should be easy to factor:
$\to x {\left(x + 4\right)}^{2} = 0$

Solution: $x = 0 \mathmr{and} x = - 4$