# How do you factor  x^3y^2+xy?

Jul 21, 2016

$x y \left({x}^{2} y + 1\right)$

#### Explanation:

Always look for a common factor first.
In this case both terns have $x y$

${x}^{3} {y}^{2} + x y$

=$x y \left({x}^{2} y + 1\right)$

Take note that anything divided by itself equals 1.

The second term of 1 must appear in the bracket. If it is left out, when we multiply out we will not get back to the original expression.