How do you factor # x^3y^2+xy#?

1 Answer
Jul 21, 2016

Answer:

#xy(x^2y +1)#

Explanation:

Always look for a common factor first.
In this case both terns have #xy#

#x^3y^2 + xy#

=#xy(x^2y +1)#

Take note that anything divided by itself equals 1.

The second term of 1 must appear in the bracket. If it is left out, when we multiply out we will not get back to the original expression.