# How do you factor x^4 + 2x^3 - 3x - 6?

$\left(x + 2\right) \left({x}^{3} - 3\right)$
1. ${x}^{4} + 2 {x}^{3} - 3 x - 6$
2. ${x}^{3} \left(x + 2\right) - 3 \left(x + 2\right)$ <- Factor out the GCF: ${x}^{3}$ for the first pair and $- 3$ for the second pair
3. $\left(x + 2\right) \left({x}^{3} - 3\right)$ <- Factor out the binomial $\left(x + 2\right)$