How do you factor # x^4+4x^2-12=0#?

1 Answer
Mar 27, 2016

Answer:

#(x - sqrt2)(x + sqrt2)(x^2 + 6)#

Explanation:

Cal #X = x^2#. Factor the quadratic function:
#f(x) = X2 + 4X - 12 = 0.#
Find 2 numbers knowing sum (+4) and product (-12). They are:
-2 and 6.
#f(x) = (X - 2)(X + 6) = (x^2 - 2)(x^2 + 6) #
#f(x) = (x - sqrt2)(x + sqrt2)(x^2 + 6)#