# How do you factor x^4-x^3-6x^2?

${x}^{2} \left(x - 2\right) \left(x + 6\right)$
Given: ${x}^{4} - {x}^{3} - 6 {x}^{2}$
Factor: $\text{ } {x}^{2} \left({x}^{2} - x - 6\right) = {x}^{2} \left(x - 2\right) \left(x + 6\right)$