How do you factor #y= 121x^2 - 1#?
This is simply a difference of squares.
#y = (11x - 1)(11x + 1)#
We can immediately factor it like this because we see that there is no
Hopefully this helps!
See a solution process below:
The right side of the equation is a special form of quadratic:
We can then write the equation factored as: