# How do you factor y^5 + 9y^2?

Sep 17, 2015

${y}^{2} \left({y}^{3} + 9\right)$

#### Explanation:

the only factor common to both is ${y}^{2}$

hence the solution is ${y}^{2} \left({y}^{3} + 9\right)$

but ${y}^{3}$ + 9 is divisible by y + (cube root of 9)

so ${y}^{3}$ + 9 = ${y}^{2}$ - (cube root of 9)y + (cube root of 9)squared

${y}^{2}$[${y}^{2}$ - (cube root of 9)y + (cube root of 9)squared]
It is ${y}^{5} + 9 {y}^{2} = {y}^{2} \left({y}^{3} + 9\right)$