How do you factor #y^5 + 9y^2#?

2 Answers

Answer:

#y^2(y^3+9)#

Explanation:

the only factor common to both is #y^2#

hence the solution is #y^2(y^3+9)#

but #y^3# + 9 is divisible by y + (cube root of 9)

so #y^3# + 9 = #y^2# - (cube root of 9)y + (cube root of 9)squared

Final answer:
#y^2#[#y^2# - (cube root of 9)y + (cube root of 9)squared]

It is #y^5+9y^2=y^2(y^3+9)#