How do you factor #y^5 + 9y^2#?

2 Answers
Christel K. · Harold Walden
Sep 17, 2015

#y^2(y^3+9)#

Explanation:

the only factor common to both is #y^2#

hence the solution is #y^2(y^3+9)#

but #y^3# + 9 is divisible by y + (cube root of 9)

so #y^3# + 9 = #y^2# - (cube root of 9)y + (cube root of 9)squared

Final answer:
#y^2#[#y^2# - (cube root of 9)y + (cube root of 9)squared]

Konstantinos Michailidis
Sep 17, 2015

It is #y^5+9y^2=y^2(y^3+9)#

Related questions
See all questions in Factoring Completely
Impact of this question
1833 views around the world
You can reuse this answer
Creative Commons License