How do you factor $y^5 + 9y^2$ ?

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Answer 1 · 2015-09-17T13:54:31

$y^2(y^3+9)$

the only factor common to both is $y^2$

hence the solution is $y^2(y^3+9)$

but $y^3$ + 9 is divisible by y + (cube root of 9)

so $y^3$ + 9 = $y^2$ - (cube root of 9)y + (cube root of 9)squared

Final answer:
$y^2$ [ $y^2$ - (cube root of 9)y + (cube root of 9)squared]

Answer 2 · 2015-09-17T13:56:11

It is $y^5+9y^2=y^2(y^3+9)$

How do you factor y^5 + 9y^2y^5 + 9y^2?