# How do you factor: #y= 8x^3 - 27 #?

##### 1 Answer

May 1, 2016

#### Answer:

#### Explanation:

This expression is a

#color(blue)" difference of cubes ""and is factorised as follows"#

#color(red)(|bar(ul(color(white)(a/a)color(black)( a^3-b^3=(a-b)(a^2+ab+b^2))color(white)(a/a)|)))# now

#8x^3=(2x)^3" and " 27=(3)^3# For factorising purposes

# a = 2x and b = 3#

#rArr 8x^3-27=(2x-3)(4x^2+6x+9)#