How do you factor: #y= s^2-8s+7 #?

2 Answers
Jun 22, 2018

Answer:

#y=s^2-8x+7hArrcolor(blue)(y=(s-7)(s-1))#

Explanation:

Since #(s+a)(s+b)=s^2+(a+b)s+ab#
we are looking for constants #a# and #b#
such that #a xx b=+7#
and #(a+b)=-8#

Jun 22, 2018

Answer:

The same processes as when you use #x#

#y=(s-1)(s-8)#

Explanation:

Note that #1xx7=7 and 1+7=8#

but we need negative 8 so we use

#(-1)xx(-7)=+7 and (-1)+(-7)=-8# as required

Thus #y=(s-1)(s-8)#