# How do you factor y= x^2-6x+5 ?

May 17, 2016

Factors are $y = \left(x - 1\right) \left(x - 5\right)$

#### Explanation:

If you have a quadratic function $a {x}^{2} + b x + c$, to factorise it you should identify two numbers whose product is $a c$ and sum is $b$.

Here in $y = {x}^{2} - 6 x + 5$, we should identify two numbers whose product is $5$ and sum is $- 6$.

Such numbers are $- 5$ and $- 1$ and now splitting middle term into these we get $y = {x}^{2} - 5 x - x + 5$ or

$y = x \left(x - 5\right) - 1 \left(x - 5\right) = \left(x - 1\right) \left(x - 5\right)$.