How do you factor #y= x^2-6x+5# ?

1 Answer
May 17, 2016

Answer:

Factors are #y=(x-1)(x-5)#

Explanation:

If you have a quadratic function #ax^2+bx+c#, to factorise it you should identify two numbers whose product is #ac# and sum is #b#.

Here in #y=x^2-6x+5#, we should identify two numbers whose product is #5# and sum is #-6#.

Such numbers are #-5# and #-1# and now splitting middle term into these we get #y=x^2-5x-x+5# or

#y=x(x-5)-1(x-5)=(x-1)(x-5)#.