# How do you factor #z^6 - 1#?

##### 2 Answers

#### Explanation:

Putting this all together we get:

If we allow complex coefficients then we can factor:

where

#### Explanation:

Remembering the formula

Now we have two ugly binomial to simplify. We could remember the formula of the difference of two perfect cubes , but it's not practical to memorize all formulas.

So what I suggest is to try to devide the two binomial by (z-1) and (z+1) that are the most probable divisors.

So the second division is perfect!

And the first division is perfect!

Now we can rewrite the initial binomial in this way: