How do you find a degree 3 polynomial function having zeros -7, 1, and -6, with a leading coefficient of 5?

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Answer 1 · 2017-10-20T11:59:33

#f(x) = 5x^3+60x^2+145x-210#

Zeros are # -7 ,1 and -6# So factors are

#(x+7) , (x-1) and (x+6)# with a leading coefficient #5#

#:. f(x) = 5 {(x+7) * (x-1)*(x+6)}# or

#f(x) = 5 {(x^2+6x-7)*(x+6)}# or

#f(x) = 5(x^3+6x^2-7x+6x^2+36x-42)# or

#f(x) = 5(x^3+12x^2+29x-42)# or

#f(x) = 5x^3+60x^2+145x-210# [Ans]