How do you find a polynomial function that has zeros 2, -6? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer AA_123 Jan 3, 2017 Answer: #f(x)=x^2+4x-12# Explanation: The zeros are #2# and #-6# Reverse their signs, you will get #-2# and #6# #(x-2)# and #(x+6)# will be a factor of the polynomial function #f(x)=(x-2)(x+6)# Multiply the two expressions #f(x)=x^2+6x-2x-12# Combine like terms #f(x)=x^2+4x-12# Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 396 views around the world You can reuse this answer Creative Commons License