How do you find a polynomial function that has zeros #x=9# and degree n=3?

1 Answer
Mar 3, 2018

Answer:

The polynomial is #x^3−27x^2+243x−729#

Explanation:

The question implies that all of the zeros of the cubic (degree 3) polynomial are at the same point, #x=9#. We can easily form the polynomial by writing it in factored form at the zero:

#(x-9)(x-9)(x-9)=0#

We can expand the left hand side to get

#x^3−27x^2+243x−729#