How do you find a vector perpendicular to the vectors v=(1 3 -2) and u=(1 2 -2)?

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Answer 1 · 2016-08-17T09:11:12

The Reqd. Vector#=(-2,0,-1)#.

It is known from the Vector Geometry that the Cross Product

or Vector Product of given two vectors #vecx# and #vecy#,

denoted by #vecx xx vecy# is a vector #bot# to both #vecx# and

#vecy#.

Hence, the Reqd. Vector#=vec v xx vec u#

#=det|(hati,hatj,hatk),(1,3,-2),(1,2,-2)|#

#=(-6+4)hati-(-2+2)hatj+(2-3)hatk#

#=-2hati-hatk#

#=(-2,0,-1)#.