How do you find #abs( 14i )#?

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Answer 1 · 2016-04-04T12:23:18

#|14i| = 14#

Given a complex number #a+bi#, the modulus #|a+bi|# of the complex number is given by

#|a+bi| = sqrt(a^2+b^2)#

In this case, we have

#|14i| = |0+14i| = sqrt(0^2+14^2) = 14#

Note that in general, for any #binRR#, we have #|bi| = sqrt(b^2) = |b|#

Answer 2 · 2016-04-04T12:25:39

14

#|ab|=|a||b|#.
i is unit vector in the direction of the axis of imaginaries. #|i|=1#.