How do you find #abs( 14i )#?

2 Answers
Apr 4, 2016

#|14i| = 14#

Explanation:

Given a complex number #a+bi#, the modulus #|a+bi|# of the complex number is given by

#|a+bi| = sqrt(a^2+b^2)#

In this case, we have

#|14i| = |0+14i| = sqrt(0^2+14^2) = 14#

Note that in general, for any #binRR#, we have #|bi| = sqrt(b^2) = |b|#

Apr 4, 2016

14

Explanation:

#|ab|=|a||b|#.
i is unit vector in the direction of the axis of imaginaries. #|i|=1#.