How do you find $| - 3 - 6 i |$ $abs( -3-6i )$ ?

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Answer 1 · 2016-05-23T14:00:55

$| - 3 - 6 i | = 3 \sqrt{5}$ $|-3-6i|=3sqrt5$

Absolute value of a complex number $a + i b$ $a+ib$ is denoted as $| a + i b |$ $|a+ib|$

and is given by $\sqrt{a^{2} + b^{2}}$ $sqrt(a^2+b^2)$

Hence absolute value $| - 3 - 6 i |$ $|-3-6i|$ is

$\sqrt{3^{2} + 6^{2}} = \sqrt{9 + 36} = \sqrt{45} = 3 \sqrt{5}$ $sqrt(3^2+6^2)=sqrt(9+36)=sqrt45=3sqrt5$

How do you find abs( -3-6i )|−3−6i|abs( -3-6i )?