How do you find all real square roots of 4?

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Answer 1 · 2017-03-13T07:29:09

The square roots of #4# are:

#sqrt(4) = 2#

#-sqrt(4) = -2#

Every positive real number #n# has exactly two real square roots.

The one we call the principal square root and denote as #sqrt(n)# is the positive one.

The other square root is #-sqrt(n)#, since:

#(-sqrt(n))^2 = (sqrt(n))^2 = n#

In the case of #4#, we find #2^2 = 4#.

So the principal square root of #4# is #2#.

The other square root is #-2#.