How do you find all the zeros of x^2 - 8x - 48 = 0?

1 Answer
Apr 29, 2016

The important thing is to be able to identify factors of 48 that add / subtract to give -8.

Explanation:

The important thing is to be able to identify factors of 48 that add / subtract to give -8.

48 could be 6*8 which doesn't work, or it could be 4*12 which does work - 4-12 = -8

Then x^2 - 8x - 48 = (x-12)(x+4)