# How do you find all zeros of the function f(x)=10x^2+5x-5?

$f \left(x\right)$ has zeros $x = \frac{1}{2}$ and $x = - 1$
$f \left(x\right) = 10 {x}^{2} + 5 x - 5 = 5 \left(2 {x}^{2} + x - 1\right) = 5 \left(2 x - 1\right) \left(x + 1\right)$
Hence $f \left(x\right)$ has zeros $x = \frac{1}{2}$ and $x = - 1$