Question

How do you find all zeros of the function `f(x) = x^3 - 6x^2 + 9x`?

Answer 1

`f(x)=0" at "x=0" ; "x=+3`

Explanation:

Notice that `x` is in each term so we can do this:

`f(x)=x(x^2-6x+9)`

Notice that `3xx3 =9" and that "3+3=6`

But we have `-6` so it has to be `-3-3=-6`

`f(x)=x(x-3)^2`

so `f(x)=0" at "x=0" ; "x=+3`