Question

How do you find all zeros of the function `x² + 2x – 48 = 0`?

Answer 1

`x=-8` or `x=6`

Explanation:

Let's factor `x^2+2x-48`

by finding two numbers whose sum is 2 and product is -48

the numbers are 8 and -6

so
`x^2+2x-48=(x+8)(x-6)`

that's zero when `x=-8` or `x=6`