# How do you find all zeros of the function x² + 2x – 48 = 0 ?

Jun 5, 2016

$x = - 8$ or $x = 6$

#### Explanation:

Let's factor ${x}^{2} + 2 x - 48$

by finding two numbers whose sum is 2 and product is -48

the numbers are 8 and -6

so
${x}^{2} + 2 x - 48 = \left(x + 8\right) \left(x - 6\right)$

that's zero when $x = - 8$ or $x = 6$