Question

How do you find an equation equivalent to `2x +3y=6` in polar coordinates?

Answer 1

Please see the explanation for the step-by-step process.

`r = 6/(2cos(theta) + 3sin(theta))`

Explanation:

Given:

`2x + 3y = 6`

Substitute `rcos(theta)` for `x` and `rsin(theta)` for `y`:

`2rcos(theta) + 3rsin(theta) = 6`

Divide both sides by `2cos(theta) + 3sin(theta)`

`r = 6/(2cos(theta) + 3sin(theta))`