Question

How do you find an equation of the line containing the given pair of points (4,5) and (12,7)?

Answer 1

The equation of the line is `x -4y = -16`

Explanation:

The slope of the line passing through `(4,5) and (12,7)` is `m= (y_2-y_1)/(x_2-x_1)= (7-5)/(12-4)=2/8=1/4`

Let the equation of the line in slope-intercept form be `y=mx+c or y=1/4x+c` The point (4,5) will satisfy the equation . So, `5= 1/4*4+c or c= 5 -1= 4`

Hence the equation of the line in slope-intercept form is `y= 1/4x+4`

The equation of the line in standard form is `y= 1/4x+4 or 4y =x+16 or x -4y = -16` {Ans]