# How do you find another point on each line using slope and point given m=-3/4; passes through (0,0)?

Mar 28, 2016

Point 1$\to \left(x , y\right) \to \left(- 3 , 2 \frac{1}{4}\right)$

Point 2$\to \left(x , y\right) \to \left(+ 3 , - 2 \frac{1}{4}\right)$

#### Explanation:

Standard form for a straight line is $y = m x + c$

We are constrained by two parameters (conditions)

If both lines pass through the point $P \to \left(x , y\right) \to \left(0 , 0\right)$

The slope $m = - \frac{3}{4}$.

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The given conditions within context of the question implies that there is only one line and that it passes through the given point.

So given condition $P \to \left(x , y\right) \to \left(0 , 0\right)$

$\implies y = m x + c \text{ "->" } 0 = m \left(0\right) + c$

This means that $c = 0$ so our equation becomes:

$y = m x$

We are told that $m = - \frac{3}{4}$

So we now have:

$y = - \frac{3}{4} x$ as our equation.

All we have to do now is substitute value for $x$ and calculate the related value for $y$ 