# How do you find domain and range for #f(x)=(x^2+2x)/(x+1) #?

##### 1 Answer

#### Answer:

The domain is

#### Explanation:

The denominator must be

Therefore,

The domain is

To calculate the range, proceed as follows :

Let

In order for this quadratic equation in

The discriminant is

Therefore,

So,

The range is

graph{(x^2+2x)/(x+1) [-16.02, 16.01, -8.01, 8.01]}