# How do you find domain and range for f(x) = (x-6)/(x+1)?

Apr 30, 2018

Below

#### Explanation:

$f \left(x\right) = \frac{x - 6}{x + 1}$

$f \left(x\right) = \frac{\left(x + 1\right) - 7}{x + 1}$

$f \left(x\right) = 1 - \frac{7}{x + 1}$

Therefore, the domain is all reals except when $x = - 1$ and range is all reals except when $y = 1$