# How do you find domain and range for #y=sqrt(x^2+4)#?

##### 1 Answer

Oct 12, 2015

#### Answer:

**Domain:**

**Range:**

#### Explanation:

**Domain**

The first thing you should consider is that the number inside the radical should be nonnegative so it won't be imaginary. We can compute for the domain by solving the inequality

Since any real number you substitute into

**Range**

The lowest value the radical can have is