# How do you find dy/dx given x=3y^3+2y?

Nov 29, 2017

$9 {y}^{2} + \setminus \frac{1}{2 y}$

#### Explanation:

I’m assuming you’re asking for the derivative of the RHS:

$3 {y}^{3} + 2 y \setminus \frac{\mathrm{dy}}{\mathrm{dx}}$

In that case, apply the power rule to each term.

$3 {y}^{3} \setminus \frac{\mathrm{dy}}{\mathrm{dx}} + 2 y \setminus \frac{\mathrm{dy}}{\mathrm{dx}}$

$= 9 {y}^{2} + \setminus \frac{1}{2 y}$