# How do you find f(-5) given f(x) = 1/2abs [t + 3]?

This make some sense if t = x and $f \left(x\right) = \frac{1}{2} | x + 3 |$
$f \left(- 5\right) = \frac{1}{2} \cdot | - 5 + 3 | = \frac{1}{2} \cdot 2$