# How do you find (f-g)(x) given f(x)=x^2-1 and g(x)=2x-3 and h(x)=1-4x#?

Apr 11, 2017

See the entire solution process below:

#### Explanation:

$\left(f - g\right) \left(x\right) = f \left(x\right) - g \left(x\right) = \left({x}^{2} - 1\right) - \left(2 x - 3\right)$

$\left(f - g\right) \left(x\right) = {x}^{2} - 1 - 2 x + 3$

$\left(f - g\right) \left(x\right) = {x}^{2} - 2 x + 3 - 1$

$\left(f - g\right) \left(x\right) = {x}^{2} - 2 x + 2$

The $h \left(x\right)$ is not used and is extraneous and unnecessary information for this problem.