How do you find five ordered pairs of #y^2 = x#?

1 Answer
marfre
Jul 18, 2018

#(0, 0), (1, -1), (1, 1), (4, 2), (4, -2)#

Explanation:

Given: #y^2 = x#

Rewrite the equation in #y = # form by square rooting both sides:

#y = +- sqrt(x)#

Since #x# is the independent variable, we can select values that we want to use to calculate #y#:

#ul(" "x" "|" "y" ")#
#" "0" "|" "sqrt(0) = 0#
#" "1" "|""+sqrt(1) = 1#
#" "1" "|""-sqrt(1) = -1#
#" "4" "|""+sqrt(4) = 2#
#" "4" "|""-sqrt(4) = -2#

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