# How do you find (fog)(x) given f(x)=6x^2 and g(x)=14x+4?

Jan 29, 2017

The answer is $= 6 {\left(14 x + 4\right)}^{2}$

#### Explanation:

This is a composition of functions

$f \left(x\right) = 6 {x}^{2}$

$g \left(x\right) = 14 x + 4$

$\left(f o g\right) \left(x\right) = f \left(g \left(x\right)\right) = f \left(14 x + 4\right)$

$= 6 {\left(14 x + 4\right)}^{2}$