How do you find in standard form a line that is parallel to #-2x-3y = -2# and passing through (2, -2)?

1 Answer
Mar 23, 2018

Answer:

#-2x-3y=2#

Explanation:

First, we need to find the slope of the line that it is parallel to, as this line will have the same slope.
#-2x-3y=-2#
#3y=-2x-2#
#y=-2/3x-2/3#
Therefore, #m=-2/3#
We can use point-slope form at first before we convert it to standard form.
#y-y_1=m(x-x_1)#
#y+2=-2/3(x-2)#
#y+2=-2/3x+4/3#
#3y+6=-2x+4# multiply by 3 to get rid of fractions
#-2x-3y=2#