How do you find in standard form a line that is parallel to -2x-3y = -2 and passing through (2, -2)?

1 Answer
Mar 23, 2018

-2x-3y=2

Explanation:

First, we need to find the slope of the line that it is parallel to, as this line will have the same slope.
-2x-3y=-2
3y=-2x-2
y=-2/3x-2/3
Therefore, m=-2/3
We can use point-slope form at first before we convert it to standard form.
y-y_1=m(x-x_1)
y+2=-2/3(x-2)
y+2=-2/3x+4/3
3y+6=-2x+4 multiply by 3 to get rid of fractions
-2x-3y=2