Question

How do you find `\log _ { 2} 1. 3125`?

Answer 1

`log_2 1.3125 ~~ 0.3923`

Explanation:

We know change base formula for logarithm is

`log_bN= log_10N/log_10b =log N/log b`

`:.log_2 1.3125 = log 1.3125/log 2 ~~ 0.3923 (4dp)` [Ans]