# How do you find oblique asymptote of #(x^2 + x + 3) /(x-1)#?

##### 1 Answer

Jun 20, 2015

#### Answer:

Partially divide the numerator by the denominator to get:

Hence the oblique asymptote is

#### Explanation:

with exclusion

So the oblique asymptote is

graph{(y - (x^2+x+3) / (x-1))(y - x - 2) = 0 [-40, 40, -20, 20]}