# How do you find sin theta if cos theta = 3/5 and theta terminates in Q 1?

Jun 9, 2015

${\sin}^{2} x = 1 - {\cos}^{2} x = 1 - \frac{9}{25} = \frac{16}{25}$ ->
--> $\sin x = \pm \frac{4}{5.}$