Convert the equation into slope-intercept form by solving for #y#.

#-5y=-9x+4 # => subtracting both sides by -9x

#y=9/5x-4/5# = > dividing by -5

The slope-intercept equation takes the form of #y=mx+b#. The slope #m# would be the coefficient of x, and the constant #b#, the y-intercept (value of #y# if #x=0#), thus yielding: #m=9/5# and #b=-4/5#.

This gives us one point on the line: #(0,-4/5)#.

To get another point on the line, substitute any number for x and solve for y. For ease in graphing, choose an integer close to the first point. For this example, let #x=1#.

#y=9/5*(1)-4/5# => by substitution

#y=9/5-4/5=5/5or 1#

Thus, point #(1,1)# also belongs to the line. From here, the two points can be connected, and a line can be formed accordingly.

graph{9x-5y=4 [-2.657, 2.657, -1.328, 1.328]}

Source: https://www.mathplanet.com/education/algebra-1/formulating-linear-equations/writing-linear-equations-using-the-slope-intercept-form